python计算两个矩形框重合百分比的实例-创新互联

如下所示：

创新互联建站主要从事做网站、成都网站设计、网页设计、企业做网站、公司建网站等业务。立足成都服务德惠,10余年网站建设经验,价格优惠、服务专业,欢迎来电咨询建站服务:18982081108

def mat_inter(box1,box2):
 # 判断两个矩形是否相交
 # box=(xA,yA,xB,yB)
 x01, y01, x02, y02 = box1
 x11, y11, x12, y12 = box2
 
 lx = abs((x01 + x02) / 2 - (x11 + x12) / 2)
 ly = abs((y01 + y02) / 2 - (y11 + y12) / 2)
 sax = abs(x01 - x02)
 sbx = abs(x11 - x12)
 say = abs(y01 - y02)
 sby = abs(y11 - y12)
 if lx <= (sax + sbx) / 2 and ly <= (say + sby) / 2:
 return True
 else:
 return False
 
def solve_coincide(box1,box2):
 # box=(xA,yA,xB,yB)
 # 计算两个矩形框的重合度
 if mat_inter(box1,box2)==True:
 x01, y01, x02, y02 = box1
 x11, y11, x12, y12 = box2
 col=min(x02,x12)-max(x01,x11)
 row=min(y02,y12)-max(y01,y11)
 intersection=col*row
 area1=(x02-x01)*(y02-y01)
 area2=(x12-x11)*(y12-y11)
 coincide=intersection/(area1+area2-intersection)
 return coincide
 else:
 return False

网页题目：python计算两个矩形框重合百分比的实例-创新互联
网站URL：http://bzwzjz.com/article/pdssj.html