本篇文章为大家展示了使用Unity3D怎么制作一个五子棋游戏，内容简明扼要并且容易理解，绝对能使你眼前一亮，通过这篇文章的详细介绍希望你能有所收获。
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using UnityEngine;
using System.Collections;
public class chess : MonoBehaviour
{
//四个锚点位置，用于计算棋子落点
public GameObject LeftTop;
public GameObject RightTop;
public GameObject LeftBottom;
public GameObject RightBottom;
//主摄像机
public Camera cam;
//锚点在屏幕上的映射位置
Vector3 LTPos;
Vector3 RTPos;
Vector3 LBPos;
Vector3 RBPos;
Vector3 PointPos;//当前点选的位置
float gridWidth = 1; //棋盘网格宽度
float gridHeight = 1; //棋盘网格高度
float minGridDis; //网格宽和高中较小的一个
Vector2[,] chessPos; //存储棋盘上所有可以落子的位置
int[,] chessState; //存储棋盘位置上的落子状态
enum turn { black, white };
turn chessTurn; //落子顺序
public Texture2D white; //白棋子
public Texture2D black; //黑棋子
public Texture2D blackWin; //白子获胜提示图
public Texture2D whiteWin; //黑子获胜提示图
int winner = 0; //获胜方，1为黑子，-1为白子
bool isPlaying = true; //是否处于对弈状态
void Start()
{
chessPos = new Vector2[15, 15];
chessState = new int[17, 16];/*原来定义是new int[15, 15]，这里将原来数组chessState上、下和右边各加一排数据，
也就相当于在棋盘的上、下和右边各填加一排隐形的棋道。原因后面解释*/
chessTurn = turn.black;
//计算锚点位置
LTPos = cam.WorldToScreenPoint(LeftTop.transform.position);
RTPos = cam.WorldToScreenPoint(RightTop.transform.position);
LBPos = cam.WorldToScreenPoint(LeftBottom.transform.position);
RBPos = cam.WorldToScreenPoint(RightBottom.transform.position);
//计算网格宽度
gridWidth = (RTPos.x - LTPos.x) / 14;
gridHeight = (LTPos.y - LBPos.y) / 14;
minGridDis = gridWidth < gridHeight ? gridWidth : gridHeight;
//计算落子点位置
for (int i = 0; i < 15; i++)
{
for (int j = 0; j < 15; j++)
{
chessPos[i, j] = new Vector2(LBPos.x + gridWidth * j, LBPos.y + gridHeight * i);//这里和源程序定义稍有不同，这里i定位行，j为列
}
}
}
void Update()
{
//检测鼠标输入并确定落子状态
if (isPlaying && Input.GetMouseButtonDown(0))
{
PointPos = Input.mousePosition;
for (int i = 0; i < 15; i++)
{
for (int j = 0; j < 15; j++)
{
//找到最接近鼠标点击位置的落子点，如果空则落子
if (Dis(PointPos, chessPos[i, j]) < minGridDis / 2 && chessState[i + 1, j] == 0)/*这里chessState行要加1，
因为上、下和右边各多加了一排，要空出来，chessPos的i行对应chessState的i+1行*/
{
//根据下棋顺序确定落子颜色
chessState[i + 1, j] = chessTurn == turn.black ? 1 : -1;//同理
//落子成功，更换下棋顺序
chessTurn = chessTurn == turn.black ? turn.white : turn.black;
}
}
}
//调用判断函数，确定是否有获胜方
int re = result();
if (re == 1)
{
Debug.Log("黑棋胜");
winner = 1;
isPlaying = false;
}
else if (re == -1)
{
Debug.Log("白棋胜");
winner = -1;
isPlaying = false;
}
}
//按下空格重新开始游戏
if (Input.GetKeyDown(KeyCode.Space))
{
for (int i = 0; i < 15; i++)
{
for (int j = 0; j < 15; j++)
{
chessState[i + 1, j] = 0;//同理
}
}
isPlaying = true;
chessTurn = turn.black;
winner = 0;
}
}
//计算平面距离函数
float Dis(Vector3 mPos, Vector2 gridPos)
{
return Mathf.Sqrt(Mathf.Pow(mPos.x - gridPos.x, 2) + Mathf.Pow(mPos.y - gridPos.y, 2));
}
void OnGUI()
{
//绘制棋子
for (int i = 0; i < 15; i++)
{
for (int j = 0; j < 15; j++)
{
if (chessState[i + 1, j] == 1)//同理
{
GUI.DrawTexture(new Rect(chessPos[i, j].x - gridWidth / 2, Screen.height - chessPos[i, j].y - gridHeight / 2, gridWidth, gridHeight), black);
}
if (chessState[i + 1, j] == -1)//同理
{
GUI.DrawTexture(new Rect(chessPos[i, j].x - gridWidth / 2, Screen.height - chessPos[i, j].y - gridHeight / 2, gridWidth, gridHeight), white);
}
}
}
//根据获胜状态，弹出相应的胜利图片
if (winner == 1)
{
GUI.DrawTexture(new Rect(Screen.width * 0.25f, Screen.height * 0.25f, Screen.width * 0.5f, Screen.height * 0.25f), blackWin);
}
if (winner == -1)
GUI.DrawTexture(new Rect(Screen.width * 0.25f, Screen.height * 0.25f, Screen.width * 0.5f, Screen.height * 0.25f), whiteWin);
}
//改写result函数
/*解释：C语言中，这样的表达式：chessState[i]&&chessState[i+1]&&chessState[i+2]&&chessState[i+3]&&chessState[i+4]，如果
* chessState[i]为False,则不管B是真是假或者是异常都不会运行，利用这一点，在chessState的右边、上边和下边各加一行为0的数据，
* 这样在判断连续五个棋子的状态时，就不用担心chessState数组的索引值超出范围。例如：chessState[i+4]的索引值i+4刚好超出范围，
* 通过在原来数组chessState的上、下和右边个添加一排为0的数，这样chessState[i+3]==0，于是就可以避免引起异常，从而简化代码*/
int result()
{
int flag = 0;
if (chessTurn == turn.white)
{
for (int i = 1; i <= 15; i++)//这里的i从1开始
{
for (int j = 0; j <= 14; j++)//j不用变
{
if ((chessState[i, j] == 1 && chessState[i, j + 1] == 1 && chessState[i, j + 2] == 1 && chessState[i, j + 3] == 1 && chessState[i, j + 4] == 1)//向右横向
|| (chessState[i, j] == 1 && chessState[i + 1, j] == 1 && chessState[i + 2, j] == 1 && chessState[i + 3, j] == 1 && chessState[i + 4, j] == 1)//向上横向
|| (chessState[i, j] == 1 && chessState[i + 1, j + 1] == 1 && chessState[i + 2, j + 2] == 1 && chessState[i + 3, j + 3] == 1 && chessState[i + 4, j + 4] == 1)//向右上斜向
|| (chessState[i, j] == 1 && chessState[i - 1, j + 1] == 1 && chessState[i - 2, j + 2] == 1 && chessState[i - 3, j + 3] == 1 && chessState[i - 4, j + 4] == 1))//向右下斜向
{
flag = 1;
}
}
}
}
else if (chessTurn == turn.black)
{
for (int i = 1; i <= 15; i++)//这里的i从1开始
{
for (int j = 0; j <= 14; j++)
{
if ((chessState[i, j] == -1 && chessState[i, j + 1] == -1 && chessState[i, j + 2] == -1 && chessState[i, j + 3] == -1 && chessState[i, j + 4] == -1)
|| (chessState[i, j] == -1 && chessState[i + 1, j] == -1 && chessState[i + 2, j] == -1 && chessState[i + 3, j] == -1 && chessState[i + 4, j] == -1)
|| (chessState[i, j] == -1 && chessState[i + 1, j + 1] == -1 && chessState[i + 2, j + 2] == -1 && chessState[i + 3, j + 3] == -1 && chessState[i + 4, j + 4] == -1)
|| (chessState[i, j] == -1 && chessState[i - 1, j + 1] == -1 && chessState[i - 2, j + 2] == -1 && chessState[i - 3, j + 3] == -1 && chessState[i - 4, j + 4] == -1))
{
flag = -1;
}
}
}
}
return flag;
}
}上述内容就是使用Unity3D怎么制作一个五子棋游戏，你们学到知识或技能了吗？如果还想学到更多技能或者丰富自己的知识储备，欢迎关注创新互联行业资讯频道。