你表中的数据,根据你的题目,应该是全部显示才对。是小于5秒还是5分钟?
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下面这个是 两条数据间小于5秒的记录的查询语句
select *,timestampdiff(second,t1.time,
(select time from table3 where t1.idid order by id limit 1) ) td ,
timestampdiff(second,
(select time from table3 where t1.idid order by id desc limit 1),t1.time
) td1
from table3 t1 where timestampdiff (second,t1.time,
(select time from table3 where t1.idid order by id limit 1) )5
or
timestampdiff(second,
(select time from table3 where t1.idid order by id desc limit 1),t1.time
)5
order by t1.id
比如表里有个日期字段。
select * from 表名 where concat(year(日期字段),month(日期字段))concat(year(now()),month(now()))
SELECT * FORM tables WHERE `price ` between 1000 and 2000
between and 是包含1000和2000
或者
SELECT * FORM tables WHERE `price `1000 and `price `2000
select case when a0 then 1 else 0 end,count(*)
from table_name
where a 0
group by case when a0 then 1 else 0 end
我想到一个方法
比如要检索小于100的所有A
step1:将所有A检索出来,并以ID升序,作为表tbl1
step2:通过tbl1,算出没个A的value与前面所有A的value和,作为一个新字段allValue,表tbl2
例:select id,name,value,(select sum(t2.value) from tb1 t2 where t2.id = t1.id) allValue from tb1 t1
step3:tbl2中allValue小于100的所有数据,应该就是你想要的了
希望能帮到你