vb点虐 快速识别颜色的简单介绍

vb点虐 如何对图片实现颜色识别

没明白你意思,看看是这样么?Dim PGet As System.Drawing.Graphics = System.Drawing.Graphics.FromImage(picture)for i=1 to picture.heightfor j=1 to picture.widthPGet .GetPixel(j, i)nextnext

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在vb点虐 中，如何获取Graphics中某一指定点（像素）的颜色值？（VB语言）

要使用GetPixel函数来取得像素的颜色值，代码如下：

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private void button1_Click(object sender, EventArgs e)

{

Color color = new Bitmap(pictureBox1.Image).GetPixel(10, 10);

MessageBox.Show(color.ToString());

怎么用vb识别出图片任意一点的颜色值？

'API函数声明

Option Explicit

Private Declare Function BitBlt Lib "gdi32" (ByVal hDestDC As Long, ByVal x As Long, ByVal y As Long, _

ByVal nWidth As Long, ByVal nHeight As Long, ByVal hSrcDC As Long, ByVal xSrc As Long, _

ByVal ySrc As Long, ByVal dwRop As Long) As Long

Private Declare Function GetCursorPos Lib "user32" (lpPoint As POINTAPI) As Long

Private Declare Function GetDC Lib "user32" (ByVal hwnd As Long) As Long

Private Declare Function GetPixel Lib "gdi32" (ByVal hdc As Long, ByVal x As Long, _

ByVal y As Long) As Long

Private Type POINTAPI '创建用户自定义的类型

x As Long '定义X的数据类型

y As Long '定义Y的数据类型

End Type

Private Sub Timer1_Timer()

Dim P1 As POINTAPI, h As Long, h1 As Long, r1 As Long

GetCursorPos P1

h1 = GetDC(h)

r1 = GetPixel(h1, P1.x, P1.y)

If r1 = -1 Then

BitBlt Picture1.hdc, 0, 0, 1, 1, h1, P1.x, P1.y, vbSrcCopy

r1 = Picture1.Point(0, 0)

Else

Picture1.PSet (0, 0), r1

End If

label2.Caption = Hex$(r1)

Picture1.BackColor = r1

End Sub

Private Sub Command1_Click()

End

End Sub

vb点虐 拾色器设计，要求：能获取图片任意位置的颜色

VB可使用Point方法来获取图片指定点的颜色。

Point 方法

按照长整数，返回在 Form 或 PictureBox 上所指定磅的红-绿-蓝 (RGB) 颜色。

语法

object.Point(x, y)

'窗体判色代码:

Private Sub Form1_MouseMove(Button As Integer, Shift As Integer, X As Single, Y As Single)

Text1 = X

Text2 = Y

Text3 = Point(X, Y)

Text4 = (Val(Text3) Mod 65536) Mod 256 'Red

Text5 = (Val(Text3) Mod 65536) \ 256 'Green

Text6 = Val(Text3) \ 65536 'Blue

Shape1.FillColor = RGB(Val(Text4), Val(Text5), Val(Text6))

End Sub

'PictureBox判色代码:

Private Sub Picture1_MouseMove(Button As Integer, Shift As Integer, X As Single, Y As Single)

Text1 = X

Text2 = Y

Text3 = Picture1.Point(X, Y)

Text4 = (Val(Text3) Mod 65536) Mod 256 'Red

Text5 = (Val(Text3) Mod 65536) \ 256 'Green

Text6 = Val(Text3) \ 65536 'Blue

Shape1.FillColor = RGB(Val(Text4), Val(Text5), Val(Text6))

End Sub

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